Question

Fill in the blank.

${\left[Ni{\left(CN\right)}_4\right]}^{2-}$ is _____ in shape whereas the shape of ${\left[Ni{\left(Cl\right)}_4\right]}^{2-}$ is ______,

Answer 1

$\left[Ni\right(CN{)}_4{]}^{2-}$ is a square planar. But $\left[Ni\right(Cl{)}_4{]}^{2-}$ is tetrahedral. Here, co-ordination number is same. But the difference occurs at hybridization and unpaired electrons.

$\left[Ni\right(CN{)}_4{]}^{2-}$ has $ds{p}^2$ hybridization without unpaired electrons.

$\left[Ni\right(Cl{)}_4{]}^{2-}$ has $s{p}^3$ hybridization with unpaired electrons.