Question

Fill in the blank: $[\frac{6}{5}\times \left(\frac{-2}{12}\right)]+[\frac{6}{5}\times \frac{4}{12}]=\frac{6}{5}\times [.....+\frac{4}{12}]$

• A. $\left(\frac{-2}{12}\right)$
• B. $\left(\frac{-1}{12}\right)$
• C. $-12$
• D. $\frac{4}{12}$

Answer 1

The correct option is A $\left(\frac{-2}{12}\right)$

Distributive property over addition for rational numbers states that
$(a\times b)+(a\times c)=a\times (b+c)$
$\therefore [\frac{6}{5}\times \left(\frac{-2}{12}\right)]+[\frac{6}{5}\times \frac{4}{12}]$
$=\frac{6}{5}[\left(\frac{-2}{12}\right)+\frac{4}{12}]$.