Question

Fill in the blank to make the expression a perfect square ${\mathrm{w}}^2-16\mathrm{w}+\square$

Answer 1

Simplify the expression to get a perfect square:

Given, the expression is ${\mathrm{w}}^2-16\mathrm{w}+\square$.

Divide the coefficient value of $\mathrm{w}$ by $2$

Here, the coefficient of the given expression is $16$

$\begin{array}{rcl}\frac{\mathrm{coefficient}}{2}& =& \frac{16}{2}\\ & =& 8\end{array}$

In order to get a perfect square, take the squared Value of the $8$

Thus, $8^2=64$

Therefore, the value $64$ is missing from the expression.