Fill in the blanks 0-000729-3-4- 0-09-3-4 -

The correct option is C 10^63^6 (0.000729)^ 3/4× (0.09)^ 3/4 ⇒ (729× 9× 10^ 8)^ 3/4 ⇒ (3^8× 10^ 8)^ 3/4 ⇒10^63^6 ...

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Byju's Answer

Standard IX

Mathematics

Laws of Exponents for Real Numbers

Fill in the b...

Question

Fill in the blanks
$(0.000729)^{- 3 / 4} \times (0.09)^{- 3 / 4} =$ _____.

\frac{10^{3}}{3^{3}}

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\frac{10^{5}}{3^{5}}

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\frac{10^{2}}{3^{2}}

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\frac{10^{6}}{3^{6}}

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Solution

The correct option is C $\frac{10^{6}}{3^{6}}$
$(0.000729)^{- 3 / 4} \times (0.09)^{- 3 / 4}$
$\Rightarrow (729 \times 9 \times 10^{- 8})^{- 3 / 4}$
$\Rightarrow (3^{8} \times 10^{- 8})^{- 3 / 4}$
$\Rightarrow \frac{10^{6}}{3^{6}}$

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Similar questions

Write the numeral whose expanded form is given below:
(i) $6 \times 10^{4} + 3 \times 10^{3} + 0 \times 10^{2} + 7 \times 10^{1} + 8 \times 10^{0}$
(ii) $9 \times 10^{6} + 7 \times 10^{5} + 0 \times 10^{4} + 3 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 2 \times 10^{0}$
(iii) $8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 2 \times 10^{2} + 9 \times 10^{1} + 6 \times 10^{0}$

4 \times 10^{5} + 5 \times 10^{3} + 3 \times 10^{2} + 2 \times 10^{2} =

Express the following standard form.

(a) 5 × 10⁶ + 4 × 10⁵ + 2 × 10³ + 9 × 10² + 6 × 10⁰

(b) 4 × 10⁵ + 8 ×10³ + 7 × 10¹

Q. Write the number :

4 \times 10^{6} + 8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 4 \times 10^{2} + 6 \times 10 + 9 \times 10^{0}

(0.000729)^{- 3 / 4} \times (0.09)^{- 3 / 4}

9^{- 3} X

, find

X

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Fill in the blanks (0.000729)−3/4×(0.09)−3/4=_____.

The correct option is C 10636(0.000729)−3/4×(0.09)−3/4⇒(729×9×10−8)−3/4⇒(38×10−8)−3/4⇒10636

Fill in the blanks
$(0.000729)^{- 3 / 4} \times (0.09)^{- 3 / 4} =$ _____.

The correct option is C $\frac{10^{6}}{3^{6}}$
$(0.000729)^{- 3 / 4} \times (0.09)^{- 3 / 4}$
$\Rightarrow (729 \times 9 \times 10^{- 8})^{- 3 / 4}$
$\Rightarrow (3^{8} \times 10^{- 8})^{- 3 / 4}$
$\Rightarrow \frac{10^{6}}{3^{6}}$