Fill in the blanks:
$10^{2} + 1^{2} + 10^{2} = 10^{2}$
$12^{2} + 2^{2} + 6^{2} = 12^{2}$
$14^{2} + 7^{2}$ + =

3^{2}, 14^{2}

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2^{2}, 14^{2}

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2^{2}, 7^{2}

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2^{2}, 12^{2}

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Solution

The correct option is C $2^{2}, 14^{2}$
From the pattern, the third number is the division of the first two number.
The fourth number can be obtained by same as the first number.
Then, the missing numbers will be
$14^{2} + 7^{2} + 2^{2} = 14^{2}$
So, $2^{2}, 14^{2}$ are the missing numbers.

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