Question

Fill in the blanks:

$191+347+963=\_\_\_+191+963$

Answer 1

Given : $191+347+963=\_\_\_+191+963$

We know property of addition, If three or more numbers are added in different groups, their sum remains the same in all cases.

i.e., $\mathrm{a}+\mathrm{b}+\mathrm{c}=\mathrm{b}+\mathrm{a}+\mathrm{c}$

Here, $\mathrm{a}=191,\mathrm{b}=347$ and $\mathrm{c}=963$

So, $191+347+963=\mathbf{347}+191+963$.