Question

Fill in the blanks:

$3\frac{5}{6}-\_\_\_=1\frac{5}{6}$

Answer 1

Step 1: Write the mixed number as an improper fraction.

$\frac{\left(6\times 3\right)+5}{6}-\_\_\_=\frac{\left(6\times 1\right)+5}{6}$

$\frac{23}{6}-\_\_\_=\frac{11}{6}$

Step 2: Transpose the fractions to the left side of the equation and blank to the right side of the equation.

$\frac{23}{6}-\frac{11}{6}=\_\_\_$

Step 3: Perform the subtraction keeping the common denominator.

$\frac{23-11}{6}=\_\_\_$

$\frac{12}{6}=\_\_\_$

Step 4. Divide both the numerator and denominator by the common factor $6$.

$\frac{12÷6}{6÷6}=\_\_\_$

$2=\_\_\_$

Hence, the required number is $\mathbf{2}$.