Question

Fill In The Blanks

A die is thrown 1000 times and the outcomes were recorded as follows:

Outcomes: 1 2 3 4 5 6
Frequency: 180 150 160 170 150 190

If the die is thown once more, then the probability that its show 5 is _________.

Answer 1

It is given that a die is thrown 1000 times.

∴ Total number of trials = 1000

Let E be the event that the die shows 5.

Number of trials of getting 5 on the die = Frequency of getting 5 on the die = 150

∴ P(Die shows the number 5) = P(E) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{trials}\mathrm{of}\mathrm{getting}5\mathrm{on}\mathrm{the}\mathrm{die}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{trials}}=\frac{150}{1000}=\frac{3}{20}$

Thus, the probability that die shows 5 is $\frac{3}{20}$.

If the die is thrown once more, then the probability that its show 5 is $\underline{\frac{3}{20}}$.