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Question

Fill in the blanks.
A horizontal pipeline carries water in streamline flow. At a point along the pipe, where the cross-sectional area is 10 cm2, the water velocity is 1 ms1 and the pressure is 2000 Pa. The pressure of water at another point where the cross-sectional area is 5 cm2 is _______ Pa ( density of water =103 kg m3 )

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Solution

As we know,
a1v1=a2v2
ATQ,
a1=10cm2=103m2
v1=1m/s=1m/s
a2=5cm2=5×104m2
v2=103×15×104=2m/s
Now, from Bowneil's theorem we get
P1+ρv212+ρgh1=P2+ρv222+ρgh2
ATQ, h1=h2
P2=P1+ρ2(v21v22)
=2000+10002(14)
=20001500
P2=500Pa


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