Question

Fill in the blanks
${\left(\begin{array}{c}\left(\right(625{)}^{-\frac{1}{2}}{)}^{\frac{-1}{4}}\end{array}\right)}^2=$___________.

• A. $4$
• B. $5$
• C. $2$
• D. $3$

Answer 1

Answer: (B)

$5$

${\left[\right(\left(625{)}^{-1/2}{)}^{-1/4}\right]}^2$

$\Rightarrow ({25}^2{)}^{(-1/2)}\times \frac{-1}{4}\times 2)$

$\Rightarrow (25{)}^{1/2}=5$