Fill in the blanks -1x-12-2-3 -

The correct option is C 1x^2 (√( ( 1x )) 12 )^ 2/3 #160; ⇒ ( 1x )^ 12×^ 14× ^ 23 #160; ⇒1x^2 ...

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Multiplication of Matrices

Fill in the b...

Question

Fill in the blanks
${∣ ∣ ∣ \begin{matrix} \sqrt[4]{(\frac{1}{x})^{- 12}} \end{matrix} ∣ ∣ ∣}^{- 2 / 3} =$ ___.

\frac{1}{x^{2}}

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\frac{1}{x^{4}}

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\frac{1}{x^{3}}

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\frac{1}{x}

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Solution

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Similar questions

If $x + \frac{1}{x} = 3$ , calculate $x^{2} + \frac{1}{x^{2}}, x^{3} + \frac{1}{x^{3}} a n d x^{4} + \frac{1}{x^{4}}$ .

\int \frac{(x + a)^{3}}{x^{3}} + \frac{1 - x^{4}}{1 - x} - \frac{7}{x \sqrt{(x^{2} - 1)}} + \frac{x + 2}{(x^{2} + 1)^{2}} + \frac{(1 + x)^{3}}{\sqrt{(x)}} d x

x + k a l o g x - k \frac{a^{2}}{x} - \frac{a^{m}}{n x^{2}} + x + \frac{x^{2}}{2} + \frac{x^{3}}{3} + \frac{x^{4}}{4}

- 7 {sec}^{- 1} x + l o g (x + 1) - \frac{1}{x + 1} + 2 \sqrt{x} + 2 x^{3 / 2} + \frac{p}{5} x^{5 / 2} + \frac{2}{r} x^{7 / 2}

k + m + n + p - r

\int (x + x^{2} + x^{3} + x^{4})

x \neq 0

x + \frac{1}{x} = 2

x^{2} + \frac{1}{x^{2}} = x^{3} + \frac{1}{x^{3}} = x^{4} + \frac{1}{x^{4}}

Now in each of the pairs of polynomials given below, check whether the first is a factor of the second:

(i) x + 1, x³ − 1

(ii) x − 1, x³ + 1

(iii) x + 1, x³ + 1

(iv) x² − 1, x⁴ − 1

(v) x − 1, x⁴ − 1

(vi) x + 1, x⁴ − 1

(vii) x − 2, x² − 5x + 1

(viii) x + 2, x² + 5x + 6

(ix)

(x) 1.3x − 2.6, x² − 5x + 6

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