Question

Fill in the blanks:

$\_\_\_-\frac{1}{3}=\frac{1}{2}$

Answer 1

Step 1: Write all the fractions with the least common denominator (LCD), $6$.

$\_\_\_-\frac{1\times 2}{3\times 2}=\frac{1\times 3}{2\times 3}$

$\_\_\_-\frac{2}{6}=\frac{3}{6}$

Step 2: Transpose the fractions to the right side of the equation and solve for blank.

$\_\_\_=\frac{3}{6}+\frac{2}{6}$

Step 3: Perform the addition keeping the common denominator.

$$\begin{gathered} \_\_\_=\frac{3+2}{6} \\ \_\_\_=\frac{5}{6} \end{gathered}$$

Hence, the required number is $\frac{\mathbf{5}}{\mathbf{6}}$.