Question

Fill in the blanks:

$\frac{3}{4}-\frac{1}{12}=\_\_\_$

Answer 1

• Step 1: The least common denominator (LCD) of $4$ and $12$ is $12$. Make the denominator as $12$ for both the fractions.

$\frac{3}{4}=\frac{3\times 3}{4\times 3}=\frac{9}{12}$;

$\frac{1}{12}=\frac{1\times 1}{12\times 1}=\frac{1}{12}$

• Step 2: Subtract the numerators and write the difference over the common denominator.

$\frac{9}{12}-\frac{1}{12}=\frac{9-1}{12}=\frac{8}{12}$

• Step 3: Divide both the numerator and denominator by the common factor $4$.

$\frac{8÷4}{12÷4}=\frac{2}{3}$

• Hence, $\frac{3}{4}-\frac{1}{12}=\frac{2}{3}$.