Question

Fill in the blanks:
(i) $-4\times \frac{7}{9}=\frac{7}{9}\times ......$
(ii) $\frac{5}{11}\times \frac{-3}{8}=\frac{-3}{8}\times ......$
(iii) $\frac{1}{2}\times \left(\frac{3}{4}+\frac{-5}{12}\right)=\frac{1}{2}\times ......+......\times \frac{-5}{12}$
(iv) $\frac{-4}{5}\times \left(\frac{5}{7}+\frac{-8}{9}\right)=\left(\frac{-4}{5}\times .....\right)\times \frac{-8}{9}$

Answer 1

$$\begin{gathered} \left(\mathrm{i}\right)-4 \\ \mathrm{x}\times \mathrm{y}=\mathrm{y}\times \mathrm{x}\left(\mathrm{commutativity}\right) \\ \left(\mathrm{ii}\right)\frac{5}{11} \\ \mathrm{x}\times \mathrm{y}=\mathrm{y}\times \mathrm{x}\left(\mathrm{commutativity}\right) \\ \left(\mathrm{iii}\right)\frac{3}{4};\frac{1}{2} \\ \mathrm{x}\times (\mathrm{y}+\mathrm{z})=\mathrm{x}\times \mathrm{y}+\mathrm{x}\times \mathrm{z}(d\mathrm{istributivity}\mathrm{of}\mathrm{multiplication}\mathrm{over}\mathrm{addition}) \\ \left(\mathrm{iv}\right)\frac{5}{7} \\ \mathrm{x}\times (\mathrm{y}\times \mathrm{z})=(\mathrm{x}\times \mathrm{y})\times \mathrm{z}(a\mathrm{ssociativity}\mathrm{of}\mathrm{multiplication}) \end{gathered}$$