Fill in the blanks-i 5x2-20x-5x- ii 5x2-20x-x-4- -2 marks-

We can write, (5x^2+20x)=(5x× x+4×5x) (5x^2+20x)=5x(x+4) [1 mark] So, nbsp; (5x^2+20x)÷5x=(5x^2+20x)/5x=5x(x+4)/5x=(x+4) [0.5 mark] (5x^2+20x)÷(x+4)=(5x ...

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Byju's Answer

Standard VIII

Mathematics

Division of a Polynomial by a Polynomial

Fill in the b...

Question

Fill in the blanks.
$(i)$ $(5 x^{2} + 20 x) \div 5 x =$ _
$(i i)$ $(5 x^{2} + 20 x) \div (x + 4) =$
[2 marks]

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Solution

$We can write,$
$(5 x^{2} + 20 x) = (5 x \times x + 4 \times 5 x)$

$(5 x^{2} + 20 x) = 5 x (x + 4)$

[1 mark]

So,
$(5 x^{2} + 20 x) \div 5 x = \frac{(5 x^{2} + 20 x)}{5 x} = \frac{5 x (x + 4)}{5 x} = (x + 4)$

[0.5 mark]

$(5 x^{2} + 20 x) \div (x + 4) = \frac{(5 x^{2} + 20 x)}{(x + 4)} = \frac{5 x (x + 4)}{(x + 4)} = 5 x$
[0.5 mark]

$Therefore,$
$(i)$ $(5 x^{2} + 20 x) \div 5 x = (x + 4)$
$(i i)$ $(5 x^{2} + 20 x) \div (x + 4) = 5 x$

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Similar questions

\int \frac{5 x^{2} + 20 x + 6}{x^{3} + 2 x^{2} + x} d x

Factorize:

$5 \sqrt{5} x^{2} + 20 x + 3 \sqrt{5}$

Q. The eccentricity of the hyperbola

5 x^{2} - 4 y^{2} - 20 x + 8 y + 4 = 0

is ______________________________.

Q. Divide

(5 x^{2} + 20 x)

5 x

and choose the correct answer.

Solve :

5 x^{2} - 20 x + 15 = 0

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Fill in the blanks. (i) (5x2+20x)÷5x= _____________ (ii) (5x2+20x)÷(x+4)= ____________ [2 marks]

We can write, (5x2+20x)=(5x×x+4×5x) (5x2+20x)=5x(x+4) [1 mark] So, (5x2+20x)÷5x=(5x2+20x)5x=5x(x+4)5x=(x+4) [0.5 mark] (5x2+20x)÷(x+4)=(5x2+20x)(x+4)=5x(x+4)(x+4)=5x [0.5 mark] Therefore, (i) (5x2+20x)÷5x=(x+4) (ii) (5x2+20x)÷(x+4)=5x

Fill in the blanks.
$(i)$ $(5 x^{2} + 20 x) \div 5 x =$ _
$(i i)$ $(5 x^{2} + 20 x) \div (x + 4) =$
[2 marks]