Question

Fill in the blanks.

(i)$\left(......\right)÷\left(\frac{-7}{5}\right)=\frac{-2}{3}$
(ii) $\left(\frac{-65}{14}\right)÷\left(......\right)=2\frac{1}{2}$
(iii) $\left(\frac{-3}{8}\right)+\left(......\right)=\frac{5}{12}$
(iv) Multiplicative inverse of $-1\frac{3}{4}$is ...... .

Answer 1

$\begin{array}{l}\\ \left(\text{i}\right)(\dots ?.\mathrm{..})÷\frac{-7}{5}=\frac{-2}{3}\\ (\dots ?\dots )=\frac{-2}{3}\times \frac{-7}{5}\\ =\frac{14}{15}\\ \\ \text{(ii})\frac{-65}{14}÷(\dots ?.\mathrm{..})=2\frac{1}{2}\\ (\dots ?.\mathrm{..})=\frac{-65}{14}÷2\frac{1}{2}\\ \text{=}\frac{-65}{14}÷\frac{5}{2}\\ \text{=}\frac{-65}{14}\times \frac{2}{5}\\ \text{=}\frac{-13}{7}\\ \left(\text{iii}\right)(\dots ?...)=\frac{5}{12}-\left(\frac{-3}{8}\right)\\ =\frac{5}{12}+\frac{3}{8}\\ L.C.M.\mathrm{of}12\mathrm{and}8\mathrm{is}24.\\ \begin{array}{l}\text{=}\frac{10+9}{24}\\ =\frac{19}{24}\end{array}\\ \left(\text{iv}\right)\text{Multiplicative inverse of -1}\frac{3}{4}\text{, i.e.}\frac{-7}{4}\text{, is}\frac{-4}{7}\text{.}\end{array}$