Question

Fill in the blanks.

(i) Reciprocal of $8\frac{2}{5}$ is ...... .
(ii) $13\frac{1}{2}÷8=......$
(iii) $69\frac{3}{4}÷7\frac{3}{4}=......$
(iv) $41\frac{2}{3}\times 18\frac{3}{5}=......$
(v) $\frac{84}{98}$(in irreducible form)= ......

Answer 1

(i) The reciprocal of $8\frac{2}{5}$ is $\frac{5}{42}$.

Reciprocal of $8\frac{2}{5}$ = Reciprocal of $\frac{42}{5}$ = $\frac{5}{42}$

(ii) $13\frac{1}{2}÷8=1\frac{11}{16}$

$13\frac{1}{2}÷8=\frac{27}{2}\times \frac{1}{8}=\frac{27}{16}=1\frac{11}{16}$

(iii) $69\frac{3}{4}÷7\frac{3}{4}=9$

$69\frac{3}{4}÷7\frac{3}{4}=\frac{279}{4}÷\frac{31}{4}$

=$\frac{279}{4}\times \frac{4}{31}=\frac{279}{31}$ = 9

(iv) $41\frac{2}{3}÷18\frac{3}{5}=775$

$41\frac{2}{3}\times 18\frac{3}{5}=\frac{125}{3}\times \frac{93}{5}$

= $\frac{125}{3}\times \frac{93}{5}=\frac{25\times 31}{1\times 1}=775$

(v) $\frac{84}{98}$(irreducible form) = $\frac{6}{7}$

The HCF of 84 and 98 is 14.

∴ $\frac{84÷14}{98÷14}=\frac{6}{7}$