Question

Fill in the blanks:

i) $\sqrt[3]{3125\times 27}=3\times ...$

Answer 1

Step: Fill in the blank

Given:$\sqrt[3]{3125\times 27}=3\times ...$

$\because \sqrt[3]{3a\times b}=\sqrt[3]{3a}\times \sqrt[3]{3b}$

$\therefore \sqrt[3]{3125\times 27}=\sqrt[3]{3125}\times \sqrt[3]{327}$

$=\sqrt[3]{35\times 5\times 5}\times \sqrt[3]{33\times 3\times 3}$

$=5\times 3$

$=3\times 5$

Hence, the correct answer is $5$.