Question

Fill in the blanks:​

(ii) $3ab\times 6ax=\underset{–}{}$

Answer 1

Find the product of $3ab$ and $6ax$
To find: $3ab\times 6ax$

The multiplication of monomials can be performed by multiplication of their coeffficients and literals.

$\therefore 3ab\times 6ax$
$=(3\times 6)\times (ab\times ax)$
$=18\times a^{1+1}\times b\times x$
$=18a^{2}bx$

Hence, $3ab\times 6ax=18a^{2}bx$.
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