Question

Fill in the blanks:

$\left(ii\right)6\times 3=\underset{–}{}\text{and}6x^2\times 3x^3=\underset{–}{}$

Answer 1

Find the product of $6$ and $3$
$6\times 3=18$

Find the product of $6x^2\times 3x^3$
i.e., $6x^2\times 3x^3$

The multiplication of monomials can be performed by multiplication of their coefficients and literals.

$\therefore 6x^2\times 3x^3$
$=(6\times 3)\times (x^2\times x^3)$
$=18\times x^{2+3}$
$=18x^5$

Hence, $6\times 3=18$ and $6x^2\times 3x^3=18x^5$