Question

Fill in the blanks:

(iii) If $\frac{a}{b}$ is the additive inverse of $\frac{-c}{d}$ then $\frac{-c}{d}$ is additive inverse of ....... and so $\frac{a}{b}+\frac{-c}{d}=\frac{-c}{d}+\frac{a}{b}=........$

Answer 1

Step 1 : Find the additive inverse

Given: $\frac{a}{b}$ is the additive inverse of $\frac{-c}{d}$

So, $\frac{-c}{d}$ is the additive inverse of $\frac{a}{b}$.

Step 2 : Find their sum

We know that, the sum of two numbers which are additive inverse of each other, is zero.

So,

$\frac{a}{b}+\frac{-c}{d}=\frac{-c}{d}+\frac{a}{b}=0$

Hence,
$\frac{a}{b}+\frac{-c}{d}=\frac{-c}{d}+\frac{a}{b}=0$.