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Question

Fill in the blanks:​

(ix) 4x×5xy×3z= –––––

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Solution

To find: 4x×5xy×3z

The multiplication of monomials can be performed by multiplication of their coeffficients and literals.

4x×5xy×3z
=(4×5×3)×(x×xy×z)
=60×x1+1×y×z
=60x2yz

Hence, 4x×5xy×3z=60x2yz.

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