Question

Fill in the blanks :

$\left[2^{20}÷2^{19}\right]\times 2^0=\_\_\_\_\_\_\_\_\_$

Answer 1

By the properties of exponent, we know that -

$$\begin{gathered} a^x÷a^y=a^{x-y} \\ {a}^x\times a^y=a^{x+y} \end{gathered}$$

By using the above properties -

$$\begin{gathered} \left[2^{20}÷2^{19}\right]\times 2^0=2^{20-19}\times 2^0 \\ =2^1\times 2^0 \\ =2^{1+0} \\ =2^1=2 \end{gathered}$$

Hence, the correct answer is $2$.