Question

Fill in the blanks :

$\left(4^0\times 5^0\right)\times 6^0=\_\_\_\_\_\_\_\_\_\_\_\_$

Answer 1

By the properties of exponent, we know that -

$a^0=1$

By using the above properties -

$$\begin{gathered} \left(4^0\times 5^0\right)\times 6^0=\left(1\times 1\right)\times 1 \\ =1\times 1 \\ =1 \end{gathered}$$

Hence, the correct answer is $1$.