Question

Fill in the blanks :

${\left({\left(6161\right)}^0\right)}^{100}÷1^{101}=\_\_\_\_\_\_\_\_$

Answer 1

By the properties of exponent, we know that -

$$\begin{gathered} {\left(a^x\right)}^y=a^{x\times y} \\ {a}^0=1 \\ {1}^x=1 \end{gathered}$$

By using the above properties -

$$\begin{gathered} {\left({\left(6161\right)}^0\right)}^{100}÷1^{101}={\left(6161\right)}^{0\times 100}÷1^{101} \\ ={6161}^0÷1 \\ =1÷1 \\ =1 \end{gathered}$$

Hence, the correct answer is $1$.