Fill in the blanks to complete the proof of 2√5 as an irrational number, provided √5 is an irrational number.
Let’s assume 2√5 be a rational number
2√5=ab,b≠0
⇒√5= (i)___________ which is a (ii)_________ number.
⇒√5 is a rational number.
But √5 is an irrational number.
Hence, we have arrived at a contradiction.
∵2√5 is an irrational number.