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Question

Fill in the blanks to complete the proof of 25 as an irrational number, provided 5 is an irrational number.

Let’s assume 25 be a rational number
25=ab,b0
5= (i)___________ which is a (ii)_________ number.
5 is a rational number.
But 5 is an irrational number.
Hence, we have arrived at a contradiction.
25 is an irrational number.

A
(i) a2b , (ii) irrational
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B
(i) a2b , (ii) rational
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C
(i) a2bb , (ii) rational
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D
(i) a2bb , (ii) irrational
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Solution

The correct option is B (i) a2b , (ii) rational

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