Fill in the blanks to make the following statements true:
(i) (− 5) + (− 8) = (− 8) + (…)
(ii) − 53 + … = − 53
(iii) 17 + … = 0
(iv) [13 + (− 12)] + (…) = 13 + [(− 12) + (− 7)]
(v) (− 4) + [15 + (− 3)] = [(− 4) + 15] +

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Solution

(i) (− 5) + (− 8) = (− 8) + (-5)
(ii) − 53 + 0 = − 53
(iii) 17 + (-17) = 0
(iv) [13 + (− 12)] + (-7) = 13 + [(− 12) + (− 7)]
(v) (− 4) + [15 + (− 3)] = [(− 4) + 15] + (-3)

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Similar questions

Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
(ii) $\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} = 2$

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Fill in the blanks.

(i) $(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . .)$

(ii) $- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)$

(iii) $(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]$

(iv) $- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . .)$

(v) $\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = {\frac{19}{- 5} + (. . . . .)} + \frac{- 7}{8}$

(vi) $\frac{- 16}{7} + . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}$

Question 4(iv)
Fill in the blanks to make the following statements true:
[13 + (- 12)] + (...) = 13 + [(- 12) + (- 7)]

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

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Fill in the blanks to make the following statements true:(i) (− 5) + (− 8) = (− 8) + (…)(ii) − 53 + … = − 53(iii) 17 + … = 0(iv) [13 + (− 12)] + (…) = 13 + [(− 12) + (− 7)](v) (− 4) + [15 + (− 3)] = [(− 4) + 15] +

(i) (− 5) + (− 8) = (− 8) + (-5)(ii) − 53 + 0 = − 53(iii) 17 + (-17) = 0(iv) [13 + (− 12)] + (-7) = 13 + [(− 12) + (− 7)](v) (− 4) + [15 + (− 3)] = [(− 4) + 15] + (-3)

Fill in the blanks to make the following statements true:
(i) (− 5) + (− 8) = (− 8) + (…)
(ii) − 53 + … = − 53
(iii) 17 + … = 0
(iv) [13 + (− 12)] + (…) = 13 + [(− 12) + (− 7)]
(v) (− 4) + [15 + (− 3)] = [(− 4) + 15] +

(i) (− 5) + (− 8) = (− 8) + (-5)
(ii) − 53 + 0 = − 53
(iii) 17 + (-17) = 0
(iv) [13 + (− 12)] + (-7) = 13 + [(− 12) + (− 7)]
(v) (− 4) + [15 + (− 3)] = [(− 4) + 15] + (-3)