Question 31
Fill in the blanks to make the statement true.
3x+23x2+6y2+2x+y2+___ =5x+7y2.
Let (3x+23x2+6y2+2x+y2)+M=5x+7y2
⇒M=(5x+7y2)−(3x+23x2+6y2+2x+y2)⇒M=5x+7y2−3x−23x2−6y2−2x−y2
[With -ve sign, +ve sign in the bracket will change on opening it]
⇒M=5x−3x−2x+7y2−6y2−y2−23x2M=0+0−23x2=−23x2