Fill in the blanks to make the statement true: $[{(7 / 11)}^{3}]^{4} = {(7 / 11)}^{- - -}$ .

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Solution

Simplifying the given expression:
To solve this we need the formula
${(a^{m})}^{n} = a^{m \times n}$
So by using the formula
$\begin{array}{rcl} [{(7 / 11)}^{3}]^{4} & = & {(7 / 11)}^{3 \times 4} \\ = & {(7 / 11)}^{12} \end{array}$
Hence, the required statement is $[{(7 / 11)}^{3}]^{4} = {(7 / 11)}^{12}$ .

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