Question 46

Fill in the blanks to make the statement true.

If area of a triangular piece of cardboard is $90 c m^{2}$ , then the length of altitude corresponding to 20 cm long base is ___ cm.

Open in App

Solution

Area of triangle $= \frac{1}{2} \times B a s e \times H e i g h t$ .
$\Rightarrow 90 = \frac{1}{2} \times 20 \times h \Rightarrow h = 9 c m$
$∴$ Altitude or height = 9 cm.

Suggest Corrections

Similar questions

Question 46

Fill in the blanks to make the statement true.

If a number is increased by 20, it becomes 45. Then, the number is .................

Q. Question 35

Fill in the blanks to make the statement true.

If a pyramid has a hexagonal base, then the number of vertices is ___.

Question 46

Fill in the blanks to make the statements true.

10g of caustic soda dissolved in 100ml of water makes a solution of caustic soda. Amount of caustic soda needed for 1 litre of water to make the same type of solution is ___.

Q. Question 32

Fill in the blanks to make the statement true.

If 4 km on a map is represented by 1 cm, then 16 km is represented by ___ cm.

Q. Question 32

Fill in the blanks to make the statement true.

If 4 km on a map is represented by 1 cm, then 16 km is represented by ___ cm.

Join BYJU'S Learning Program

Explore more

Area of a Triangle

Standard IX Mathematics

Join BYJU'S Learning Program

Question 46 Fill in the blanks to make the statement true. If area of a triangular piece of cardboard is 90 cm2, then the length of altitude corresponding to 20 cm long base is ___ cm.

Area of triangle =12×Base×Height. ⇒90=12×20×h⇒h=9cm ∴ Altitude or height = 9 cm.

Question 46

Fill in the blanks to make the statement true.

If area of a triangular piece of cardboard is $90 c m^{2}$ , then the length of altitude corresponding to 20 cm long base is ___ cm.

Area of triangle $= \frac{1}{2} \times B a s e \times H e i g h t$ .
$\Rightarrow 90 = \frac{1}{2} \times 20 \times h \Rightarrow h = 9 c m$
$∴$ Altitude or height = 9 cm.