In △ABC, AD,BE,CF are the altitudes of sides BC,AC,AB respectively.
We know that, in all the line segments that can be drawn to a given line from a point not lying on it, the perpendicular line segment is the shortest.
Now, AD⊥BC⟹AB>AD and AC>AD
⟹AB+AC>2AD ........... (i)
BE⊥AC⟹AB>BE and BC>BE
⟹AB+BC>2BE ........... (ii)
Similarly, CF⊥AB⟹AC>CF and BC>CF
⟹AC+BC>2CF .......... (iii)
Adding (i),(ii) and (iii) we get
2(AB+BC+AC)>2(AD+BE+CF)
⟹AB+BC+AC>AD+BE+CF
Hence, sum of three altitudes of a triangle is less than its perimeter.