Question

Fill In The Blanks

Two coins are tossed 1000 times and outcomes are recorded as below:

Numbers of heads: 2 1 0
Frequency: 200 550 250

The probability of getting at most one head is _______.

Answer 1

Two coins are tossed 1000 times.

∴ Total number of trials = 1000

Let E be the event of getting at most one head on the two coins.

Number of trials for getting at most one head

= Frequency of getting 0 heads + Frequency of getting 1 head

= 250 + 550

= 800

∴ Probability of getting at most one head = P(E) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{trials}\mathrm{for}\mathrm{getting}\mathrm{at}\mathrm{most}\mathrm{one}\mathrm{head}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{trials}}=\frac{800}{1000}=\frac{4}{5}$

Thus, the probability of getting at most one head is $\frac{4}{5}$.

The probability of getting at most one head is $\underline{\frac{4}{5}}$.