Question

Fill in the blanks using appropriate fractions:

$\frac{12}{15}-\_\_\_=\frac{7}{15}$

Answer 1

Step 1: Subtract $\frac{12}{15}$ from both sides of the given equation and simplify.

$\frac{12}{15}-\_\_\_-\frac{12}{15}=\frac{7}{15}-\frac{12}{15}$

$-\_\_\_=\frac{7}{15}-\frac{12}{15}$

Step 2: Subtract the numerators and write the difference over the common denominator.

$$\begin{gathered} -\_\_\_=\frac{7-12}{15} \\ -\_\_\_=-\frac{5}{15} \end{gathered}$$

Step 3: Multiply both sides of the equation by $-1$.

$\_\_\_=\frac{5}{15}$

Step 4: Divide both the numerator and denominator by the common factor $5$.

$$\begin{gathered} \_\_\_=\frac{5÷5}{15÷5} \\ \_\_\_=\frac{1}{3} \end{gathered}$$

Hence, the required number is $\frac{\mathbf{1}}{\mathbf{3}}$.