1
Question
Fill in the blanks:
(vii) - 4 -6 -5 =
and -4ax - 6ax -5ay =
(vii) - 4 -6 -5 =
and -4ax - 6ax -5ay =
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Solution
Sum of -4, -6 and -5 =(−4)+(−6)+(−5)
=−4−6−5
=−(4+6+5)
=−15
Sum of -4ax, -6ax and -5ay
=(−4ax)+(−6ax)+(−5ay)
=−4ax−6ax−5ay
=−ax(4+6)−5ay
=−10ax−5ay
Hence, −4−6−5=−15 and
−4ax−6ax−5ay=−10ax−5ay
=−4−6−5
=−(4+6+5)
=−15
Sum of -4ax, -6ax and -5ay
=(−4ax)+(−6ax)+(−5ay)
=−4ax−6ax−5ay
=−ax(4+6)−5ay
=−10ax−5ay
Hence, −4−6−5=−15 and
−4ax−6ax−5ay=−10ax−5ay
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