CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Fill in the blanks with the appropriate words.
The net result of glycolysis of one glucose molecule is the. formation of .......... NADH and .......... ATP

Open in App
Solution

  • Glycolysis the process of break down of glucose molecule into 2 molecules of 3 carbon pyruvate which takes place in the cytoplasm of the cell.
  • The process of glycolysis has 2 type of reaction i.e. phosphorylation and dephosphorylation reactions.
  • The first 5 reactions are phosphorylation reaction where ATP molecule is used. First ATP molecule is used in reaction for conversion of Glucose to Glucose 6 phosphate and second ATP molecule is used the reaction for conversion of Fructose 6 phosphate to Fructose 1,6 bisphosphate.
  • Also the production of NADH takes place when a 3 carbon molecule Glyceraldehyde 3-phosphate is converted to 1,3 bisphosphoglyceric acid where one H ion and one electron is also released.
  • In the dephosphorylation reaction 2 ATP molecules are released while conversion of 2 molecules of 1,3 bisphosphoglyceric acid to 2 molecules 3 phosphoglyceric acid. Second second pair of ATP molecules is released when 2 molecules of 3 carbon phosphophenolpyruvate is converted to 3 carbon molecule pyruvic acid. During both of these reactions ADP and inorganic P react to form a molecule of ATP.
  • Therefore the net gain of ATP during glycolysis is 2 ATP as 4 molecules of ATP are produced and 2 molecules of ATP are used. While 2 molecules of NADH + H are produced.
  • Therefore the answer for the first blank is 2 and the second blank is 2.
  • The net result of glycolysis of one glucose molecule is the. formation of 2 NADH and 2 ATP

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Glycolysis
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon