Question

Fill in the blanks:​

(x) $5x\times 2x^{2}y\times -7y^3\times 2x^3{y}^2=\underset{–}{}$
​

Answer 1

To find: $5x\times 2x^{2}y\times -7y^3\times 2x^3{y}^2$

The multiplication of monomials can be performed by multiplication of their coeffficients and literals.

$\therefore 5x\times 2x^{2}y\times -7y^3\times 2x^3{y}^2$
$=(5\times 2\times -7\times 2)\times (x\times x^{2}y\times y^3\times x^3{y}^2)$
$=-140\times x^{1+2+3}\times y^{1+3+2}$
$=-140x^6{y}^6$

Hence, $5x\times 2x^{2}y\times -7y^3\times 2x^3{y}^2=-140x^6{y}^6$.