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A tower is observed from two stations A and B where B is East of A at a distance 100 metres. The tower is due North of A and due North-West of B. The angles of elevation of the tower from A and B are complementary, the height of the tower is ____________.

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Solution

100(2)1/4
h=APtanθ=BPcotθ
h2=AP.BP, BP=1002 by Pythagoras.
h2=100×1002 or h=100(2)1/4
1084866_1006661_ans_70eeb34fdd4349b4b66cbb2095f3a851.png

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