Question

Fill in the boxes with the correct symbol$>,<or=$

$\frac{-7}{3}\square \frac{-9}{5}$

Answer 1

We have $\frac{-7}{3}and\frac{-9}{5}$

To compare them we have to equate their denominators.

$LCM(3,5)=15$

Now,

$\frac{-7}{3}=\frac{-7\times 5}{3\times 5}=\frac{-35}{15}$

and$\frac{-9}{5}=\frac{-9\times 3}{5\times 3}=\frac{-27}{15}$

Since,

$$\begin{gathered} \frac{35}{15}>\frac{27}{15} \\ \Rightarrow \frac{-35}{15}<\frac{-27}{15} \\ \Rightarrow \frac{-7}{3}<\frac{-9}{5} \end{gathered}$$

Thus, $\frac{-7}{3}<\frac{-9}{5}$

Hence, the required symbol is $<$