Question

Fill in the boxes with the correct symbol out of >, <, and =.
(a) $\frac{-4}{5}$ $\frac{-5}{7}$
(b)$\frac{-7}{8}$ $\frac{14}{-16}$
(c) $0$ $\frac{-7}{6}$

Answer 1

(a) $\frac{-4}{5}$ $\frac{-5}{7}$
So, $\frac{-4}{5}=\frac{-4\times 7}{5\times 7}=\frac{-28}{35}$ and
$\frac{-5}{7}=\frac{-5\times 5}{7\times 5}=\frac{-25}{35}$
$-28<-25$
So, $\frac{-28}{35}<\frac{-25}{35}$
Thus, $\frac{-4}{5}<\frac{-5}{7}$

(b) $\frac{-7}{8}$ $\frac{14}{-16}$
The standard form of $\frac{14}{-16}$ is $\frac{14÷-2}{-16÷-2}=\frac{-7}{8}$
So, $\frac{-4}{5}<\frac{-5}{7}$
Thus, $\frac{-7}{8}=\frac{14}{-16}$

(c) $0$ $\frac{-7}{6}$
Clearly, $\frac{-7}{6}$ is a negative rational number which will be less than zero.
So, $0>\frac{-7}{6}$