Fill in the empty values of the cells in the table:
$V_{1}$ $T_{1}$ $V_{2}$ $T_{2}$
A 840 K 1070 ml 147 K
B 3250 ml $475^{0}$ $50^{0}$
C 10 Litre 15 Litre $50^{0}$
Use Charles Law to fill the following table:

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Solution

Charles Law states that for an ideal gas volume is directly proportional to temperature when pressure is constant i.e, $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
$\Rightarrow$ For A $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
$\frac{V_{1}}{T 840} = \frac{1070}{147}$
$V_{1} = 6114.2 m l$

$\Rightarrow$ For B $\frac{3250}{748} = \frac{V_{2}}{323}$
$V_{2} = 1403.4 m l$

$\Rightarrow$ For C $\frac{10}{T_{1}} = \frac{15}{323}$
$V_{2} = 215 K$
Hence, solved.

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	$V_{1}$	$T_{1}$	$V_{2}$	$T_{2}$
A		840 K	1070 ml	147 K
B	3250 ml	$475^{0}$		$50^{0}$
C	10 Litre		15 Litre	$50^{0}$

Fill in the empty values of the cells in the table: V1T1V2T2A840 K1070 ml147 KB3250 ml4750500C10 Litre15 Litre500Use Charles Law to fill the following table:

Charles Law states that for an ideal gas volume is directly proportional to temperature when pressure is constant i.e, V1T1=V2T2⇒ For A V1T1=V2T2 V1T840=1070147 V1=6114.2ml⇒ For B 3250748=V2323 V2=1403.4ml⇒ For C 10T1=15323 V2=215KHence, solved.

Fill in the empty values of the cells in the table:
$V_{1}$ $T_{1}$ $V_{2}$ $T_{2}$
A 840 K 1070 ml 147 K
B 3250 ml $475^{0}$ $50^{0}$
C 10 Litre 15 Litre $50^{0}$
Use Charles Law to fill the following table: