Fill in the missing digit such that it is divisible by the given divisior. Is there more than one possible answer? If so list them
$_27413 \div 11$

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Solution

Let us consider the missing digit to be x.
We have, $x 27413 \div 11$
Therefore the difference in the sum of digits at even places to the sum of digits at odd places should be $0$ or divisible by $11$
$(x + 7 + 1) - (2 + 4 + 3) = 8 + x - 9 = x - 1$
If we take $x = 1$ then the difference will be $0$
Hence the missing digit is $1$

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Fill in the missing digit such that it is divisible by the given divisior. Is there more than one possible answer? If so list them_27413÷11

Let us consider the missing digit to be x.We have, x27413÷11 Therefore the difference in the sum of digits at even places to the sum of digits at odd places should be 0 or divisible by 11(x+7+1)-(2+4+3)=8+x-9=x-1If we takex=1 then the difference will be 0Hence the missing digit is 1

Fill in the missing digit such that it is divisible by the given divisior. Is there more than one possible answer? If so list them
$_27413 \div 11$