Question

Fill in the missing fractions:

(i) $\frac{7}{10}-\boxed{}=\frac{3}{10}$
(ii) $\boxed{}-\frac{3}{21}=\frac{5}{21}$
(iii) $\boxed{}-\frac{3}{6}=\frac{3}{6}$
(iv) $\boxed{}-\frac{5}{27}=\frac{12}{27}$

Answer 1

(i)
$$\begin{gathered} \frac{7}{10}-\square =\frac{3}{10} \\ \square =\frac{7}{10}-\frac{3}{10}=\frac{7-3}{10}=\frac{4}{10} \\ \square =\frac{4}{10} \end{gathered}$$

(ii)
$$\begin{gathered} \square -\frac{3}{21}=\frac{5}{21} \\ \square =\frac{3}{21}+\frac{5}{21}=\frac{3+5}{21}=\frac{8}{21} \end{gathered}$$

(iii)
$$\begin{gathered} \square -\frac{3}{6}=\frac{3}{6} \\ \square =\frac{3}{6}+\frac{3}{6}=\frac{3+3}{6}=\frac{6}{6}=1 \end{gathered}$$

(iv)
$$\begin{gathered} \square -\frac{5}{27}=\frac{12}{27} \\ \square =\frac{12}{27}+\frac{5}{27}=\frac{12+5}{27} \\ \square =\frac{17}{27} \end{gathered}$$