Fill in the missing number
$3, 10, 101, . . . . . . . . . . . .$

1011

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10101

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10201

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10202

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Solution

The correct option is D $10202$
In the given series
$\Rightarrow 3 \times 3 = 9 + 1 = 10$
$\Rightarrow 10 \times 10 = 100 + 1 = 101$
$\Rightarrow 101 \times 101 = 10201 + 1 = 10202$
Hence, option 'D' is correct.

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Similar questions

11^{2} = 121

101^{2} = 10201

10101^{2} = 102030201

1010101^{2} = . . . . . . . . . . . . . . . . . . . . . .

Observe the following pattern and supply the missing number.

11² = 121

101² = 10201

10101² = 102030201

1010101² = …

…² = 10203040504030201

11^{2} = 121

101^{2} = 10201

10101^{2} = 102030201

1010101^{2} = . . . . . . . . . . . . . . . .

. . . . . . . . . . . . . .^{2} = 10203040504030201

11^{2} = 121

101^{2} = 10201

10101^{2} = 102030201

1010101^{2} = 1020304030201

. . . . . . . . . . . . .^{2} = 10203040504030201

Question 5
Observe the following pattern and supply the missing numbers.

$11^{2} = 121 101^{2} = 10201 10101^{2} = 102030201 1010101^{2} = . . . . . . . . . . . . . . . . . . . . . . . . . .^{2} = 10203040504030201$

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