Fill in the missing numbers/words.
$310 + 981 + 309 = 981 + 309 +___$

Open in App

Solution

Given: $310 + 981 + 309 = 981 + 309 +___$
We know property of addition, If three or more numbers are added in different groups, their sum remains the same in all cases.
i.e., $a + b + c = b + c + a$
Here, $a = 310, b = 981$ and $c = 309$ .
So, $310 + 981 + 309 = 981 + 309 + 310$

Suggest Corrections

Similar questions

981 \div 3

= (A + B + C) \div 3

= (A + D) \div 3

= (A \div 3) + (D \div 3)

= E + 27

= F

Fill in the missing numbers/words .
$1676 + 300 =____$

Fill in the missing numbers/words.

$9999 + 1 =$

Replace $*$ by a digit to make the number exactly divisible by $9$

$7 * 309$

Fill in the missing numbers/words.
$4364 +____= 4364 .$

Join BYJU'S Learning Program