Question

Fill the following boxes with $<\text{or}>$ sign

$5.3\times 7.6\times 1\left(\right)1\times 53\times 7.6$

Answer 1

Given :

LHS $=5.3\times 7.6\times 1$

$$\begin{gathered} =\frac{53}{10}\times \frac{76}{10}\times 1 \\ =\frac{4028}{100} \\ =40.28 \end{gathered}$$

RHS $=1\times 53\times 7.6$

$$\begin{gathered} =1\times 53\times \frac{76}{10} \\ =\frac{4028}{10} \\ =402.8 \end{gathered}$$

Clearly,

$$\begin{gathered} 40.28<402.8 \\ \text{LHS}<\text{RHS} \end{gathered}$$

Hence, $\left(5.3\times 7.6\times 1\right)<\left(1\times 53\times 7.6\right)$