Final speed of the platform in situation (ii), i.e., just after B has jumped, will be nearly :

7.5 m/s

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5.5 m/s

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4.5 m/s

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2.5 m/s

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Solution

The correct option is B 2.5 m/s
$L e t t h e v e l o c i t y o f t h e p l a t f o r m b e v, t h e n t h e v e l o c i t y o f f i r s t m a n a f t e r j u m p w i l l b e v + (- 3) = v - 3. B y c o n s e r v a t i o n o f m o m e n t u m 0 = (50 + 40) \times v + 60 \times (v - 3) \Rightarrow v = \frac{6}{5} m / s F o r t h e s e c o n d j u m p, l e t t h e v e l o c i t y a f t e r i t b e V, t h e n t h e v e l o c i t y o f B w i l l b e V - 3, c o n s e r v i n g m o m e n t u m a l o n g h o r i z o n t a l d i r e c t i o n 90 \times \frac{6}{5} = 50 V + 40 (V - 3) \Rightarrow V = 2.5 m / s$

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