We have, 1.25÷2.5 =125/100÷25/100ex0ex=125/100×10/250ex0ex=1250/25000ex0ex=125/2500ex0ex=5/100ex0ex=0.5Hence, the required solution is 0.5. ...

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Standard XII

Mathematics

Applications of Cross Product

Find:-1.25÷2....

Question

Find:-
$1.25 \div 2.5$

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Solution

We have, $1.25 \div 2.5$
$= \frac{125}{100} \div \frac{25}{10} = \frac{125}{100} \times \frac{10}{25} = \frac{1250}{2500} = \frac{125}{250} = \frac{5}{10} = 0.5$
Hence, the required solution is $0.5$ .

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Find:-1.25÷2.5

We have, 1.25÷2.5 =125100÷2510=125100×1025=12502500=125250=510=0.5Hence, the required solution is 0.5.

Find:-
$1.25 \div 2.5$

We have, $1.25 \div 2.5$
$= \frac{125}{100} \div \frac{25}{10} = \frac{125}{100} \times \frac{10}{25} = \frac{1250}{2500} = \frac{125}{250} = \frac{5}{10} = 0.5$
Hence, the required solution is $0.5$ .