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Question

Find 1 + (xy) + (xy)2 + (xy)3 + …… if a= 1+ 2x + 3x2 + 4x3+….. ( -1<a<1) and b= 1+3y + 6y2 + 10y3+…. (-1<b<1)

A
(a1/2b1/3) / (a1/2 + b1/3 -1)
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B
(a1/2b1/3) / (a1/2 + b1/3 +1)
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C
(a1/2 + b1/3 +1) / (a1/2b1/3)
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D
(a1/2 + b1/3 -2) / (a1/2b1/3)
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E
(a1/2 + b1/3 +2) / (a1/2b1/3)
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Solution

The correct option is A (a1/2b1/3) / (a1/2 + b1/3 -1)

Option (a)

Assume x=0 and y=0. Then the equation gives a value of 1. Put the values of x

and y to get a and b. a=1 and b=1

Go from answer options. Only answer option a gives 1


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