Question

Find $10$ rational numbers between $-\frac{3}{11}$ and $\frac{8}{11}$

Answer 1

We know that $-3<-2<-1<0<1<2<3<4<5<6<7<8$

If we divide the above numbers by $11$ we get,

$-\frac{3}{11}<-\frac{2}{11}<-\frac{1}{11}<\frac{0}{11}<\frac{1}{11}<\frac{2}{11}<\frac{3}{11}<\frac{4}{11}<\frac{5}{11}<\frac{6}{11}<\frac{7}{11}<\frac{8}{11}$

Hence, the $10$ rational numbers between $-\frac{3}{11}$ and $\frac{8}{11}$ are as follows:

$-\frac{2}{11},-\frac{1}{11},\frac{0}{11},\frac{1}{11},\frac{2}{11},\frac{3}{11},\frac{4}{11},\frac{5}{11},\frac{6}{11},\frac{7}{11}$