Find $- 11 a c + 14 b c + 7 a b$ , if $a = 2, b = - 3$ and $c = 5$ .

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Solution

Given the algebraic expression, $- 11 a c + 14 b c + 7 a b$
For values $a = 2, b = - 3$ and $c = 5$ , putting all the values, we get:
$- 11 \times 2 \times 5 + 14 \times (- 3) \times 5 + 7 \times 2 \times (- 3) = - 110 - 210 - 42 = - 362$
Hence,the value of $- 11 a c + 14 b c + 7 a b$ for $a = 2, b = - 3$ and $c = 5$ is equal to $- 362$ .

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Find -11ac+14bc+7ab, if a=2,b=-3 and c=5.

Given the algebraic expression,-11ac+14bc+7abFor values a=2,b=-3 and c=5, putting all the values, we get:-11×2×5+14×-3×5+7×2×-3=-110-210-42=-362Hence,the value of -11ac+14bc+7ab for a=2,b=-3 and c=5 is equal to -362.

Find $- 11 a c + 14 b c + 7 a b$ , if $a = 2, b = - 3$ and $c = 5$ .